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RootBracketingSolvers QuickStart Sample (VB.NET)
Extreme Optimization Mathematics Library for .NET
RootBracketingSolvers QuickStart Sample (VB.NET)
Illustrates the use of the root bracketing
solvers (Extreme.Mathematics.EquationSolvers namespace) for solving
equations in Visual Basic .NET.
C# code
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' The RootBracketingSolver and derived classes reside in the
' Extreme.Mathematics.EquationSolvers namespace.
Imports Extreme.Mathematics.EquationSolvers
' Function delegates reside in the Extreme.Mathematics
' namespace.
Imports Extreme.Mathematics
Namespace Extreme.Mathematics.QuickStart.VB
' Illustrates the use of the root bracketing solvers
' in the Extreme.Mathematics.EquationSolvers namespace of the Extreme
' Optimization Mathematics Library for .NET.
Module RootBracketingSolvers
Sub Main()
' Root bracketing solvers are used to solve
' non-linear equations in one variable.
'
' Root bracketing solvers start with an interval
' which is known to contain a root. This interval
' is made smaller and smaller in successive
' iterations until a certain tolerance is reached,
' or the maximum number of iterations has been
' exceeded.
'
' The properties and methods that give you control
' over the iteration are shared by all classes
' that implement iterative algorithms.
'
' Target function
'
' The function we are trying to solve must be
' provided as a RealFunction. For more
' information about this delegate, see the
' Functions QuickStart sample.
Dim f As RealFunction = _
New RealFunction(AddressOf Math.Cos)
' All root bracketing solvers inherit from
' RootBracketingSolver, an abstract base class.
Dim solver As RootBracketingSolver
'
' Bisection method
'
' The bisection method halves the interval during
' each iteration. It is implemented by the
' BisectionSolver class.
Console.WriteLine("BisectionSolver: cos(x) = 0 over [1,2]")
solver = New BisectionSolver()
solver.LowerBound = 1
solver.UpperBound = 2
solver.TargetFunction = f
Dim result As Double = solver.Solve()
' The Status property indicates
' the result of running the algorithm.
Console.WriteLine(" Result: {0}", _
solver.Status)
' The result is also available through the
' Result property.
Console.WriteLine(" Solution: {0}", solver.Result)
' You can find out the estimated error of the result
' through the EstimatedError property:
Console.WriteLine(" Estimated error: {0}", _
solver.EstimatedError)
Console.WriteLine(" # iterations: {0}", _
solver.IterationsNeeded)
'
' Regula Falsi method
'
' The Regula Falsi method optimizes the selection
' of the next interval. Unfortunately, the
' optimization breaks down in some cases.
' Here is an example:
Console.WriteLine("RegulaFalsiSolver: cos(x) = 0 over [1,2]")
solver = New RegulaFalsiSolver()
solver.LowerBound = 1
solver.UpperBound = 2
solver.TargetFunction = f
result = solver.Solve()
Console.WriteLine(" Result: {0}", _
solver.Status)
Console.WriteLine(" Solution: {0}", solver.Result)
Console.WriteLine(" Estimated error: {0}", _
solver.EstimatedError)
Console.WriteLine(" # iterations: {0}", _
solver.IterationsNeeded)
' However, for sin(x) = 0, everything is fine:
Console.WriteLine("RegulaFalsiSolver: sin(x) = 0 over [-0.5,1]")
solver = New RegulaFalsiSolver()
solver.LowerBound = -0.5
solver.UpperBound = 1
solver.TargetFunction = _
New RealFunction(AddressOf Math.Sin)
result = solver.Solve()
Console.WriteLine(" Result: {0}", _
solver.Status)
Console.WriteLine(" Solution: {0}", solver.Result)
Console.WriteLine(" Estimated error: {0}", _
solver.EstimatedError)
Console.WriteLine(" # iterations: {0}", _
solver.IterationsNeeded)
'
' Dekker-Brent method
'
' The Dekker-Brent method combines the best of
' both worlds. It is the most robust and, on average,
' the fastest method.
Console.WriteLine("DekkerBrentSolver: cos(x) = 0 over [1,2]")
solver = New DekkerBrentSolver()
solver.LowerBound = 1
solver.UpperBound = 2
solver.TargetFunction = f
result = solver.Solve()
Console.WriteLine(" Result: {0}", _
solver.Status)
Console.WriteLine(" Solution: {0}", solver.Result)
Console.WriteLine(" Estimated error: {0}", _
solver.EstimatedError)
Console.WriteLine(" # iterations: {0}", _
solver.IterationsNeeded)
'
' Controlling the process
'
Console.WriteLine("Same with modified parameters:")
' You can set the maximum # of iterations:
' If the solution cannot be found in time, the
' Status will return a value of
' AlgorithmStatus.IterationLimitExceeded
solver.MaxIterations = 20
' You can specify how convergence is to be tested
' through the ConvergenceCriterion property:
solver.ConvergenceCriterion = _
ConvergenceCriterion.WithinRelativeTolerance
' And, of course, you can set the absolute or
' relative tolerance.
solver.RelativeTolerance = 0.00001
' In this example, the absolute tolerance will be
' ignored.
solver.AbsoluteTolerance = 1.0E-24
solver.LowerBound = 157081
solver.UpperBound = 157082
solver.TargetFunction = f
result = solver.Solve()
Console.WriteLine(" Result: {0}", _
solver.Status)
Console.WriteLine(" Solution: {0}", solver.Result)
' The estimated error will be less than 0.157
Console.WriteLine(" Estimated error: {0}", _
solver.EstimatedError)
Console.WriteLine(" # iterations: {0}", _
solver.IterationsNeeded)
Console.Write("Press Enter key to exit...")
Console.ReadLine()
End Sub
End Module
End Namespace
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