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Solution :

The given equation can be written as `(x^(2) + 6x)+(y^(2) - 10y) = 2` <br> Now, completing th squares within parenthesis, we get <br> `(x^(2) + 6x+9) + (y^(2) -10y +25) = 2+ 9 +25` <br> i.e., `(x+3)^(2) + (y-5)^(2) = (6)^(2)` <br> i.e., `[x-(3)]^(2) + (y -5)^(2) = (6)^(2)` <br> Therefore, the given circle has centre at `(-3, 5)` and radius 6. Image Solution

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