VectorExtensions.Lag<T>(Vector<T>) Method

Returns a vector whose observations are moved ahead by one observation.

Definition

Namespace: Extreme.DataAnalysis
Assembly: Extreme.Numerics (in Extreme.Numerics.dll) Version: 8.1.23

public static Vector<T> Lag<T>(
	this Vector<T> vector
)

Visual Basic

<ExtensionAttribute>
Public Shared Function Lag(Of T) ( 
	vector As Vector(Of T)
) As Vector(Of T)

C++/CLI

public:
[ExtensionAttribute]
generic<typename T>
static Vector<T>^ Lag(
	Vector<T>^ vector
)

[<ExtensionAttribute>]
static member Lag : 
        vector : Vector<'T> -> Vector<'T>

Vector<T>
A vector.

In Visual Basic and C#, you can call this method as an instance method on any object of type Vector<T>. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

Each new observation is the observation before the current observation. The first observation is set to NaN.

The new vector gets the name lag1(<name>), where <name> is the name of the original vector.